Now the supply voltage is doubled from 240V to 480V. The voltage between each dynode is therefore doubled as well. A photon struck the photocathode of the photomultiplier tube to the left, and an electron is being accelerated to the first dynode. How many electrons will be ejected by the first dynode?

Since the voltage between the photocathode and the first dynode is 160V, four secondary electrons are emitted. In the previous example, the voltage between the photocathode and first dynode was 80V, and two secondary electrons were emitted. After one stage, doubling the voltage also doubled the number of secondary electrons. How many electrons will there be after the second stage?

The potential between the first and second dynode is once again 160V, so each of the four electrons emitted by the first dynode ejected four more electrons, totaling 16 electrons. In the previous example when the supply voltage was only 240V, there were only four electrons after the second stage. How many electrons will there be after the third dynode?